求解JAVA编程题：编写一个程序选择法对数组a[]={20,10,50,40,30,70,60,80,90,100}进行由大到小的顺序
1个回答
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public class C {
public static void main(String[] args) {
int[] ary = {20,10,50,40,30,70,60,80,90,100};
sort(ary);
System.out.println("After sort, array item is: ");
for(int i = 0; i < ary.length; i++){
System.out.print(ary[i] + " ");
}
}
private static void sort(int[] ary) {
for(int i = 0; i < ary.length - 1; i++){
for(int j = i + 1; j < ary.length; j++){
if(ary[j] > ary[i]){
int temp = ary[i];
ary[i] = ary[j];
ary[j] = temp;
}
}
}
}
}
------------------testing
After sort, array item is:
100 90 80 70 60 50 40 30 20 10
public static void main(String[] args) {
int[] ary = {20,10,50,40,30,70,60,80,90,100};
sort(ary);
System.out.println("After sort, array item is: ");
for(int i = 0; i < ary.length; i++){
System.out.print(ary[i] + " ");
}
}
private static void sort(int[] ary) {
for(int i = 0; i < ary.length - 1; i++){
for(int j = i + 1; j < ary.length; j++){
if(ary[j] > ary[i]){
int temp = ary[i];
ary[i] = ary[j];
ary[j] = temp;
}
}
}
}
}
------------------testing
After sort, array item is:
100 90 80 70 60 50 40 30 20 10
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