Question

不等式2的x-3/x+1次方<=1/2

Answer 1

2^[x-3/(x+1)]≤2^(-1)
因为2>1
所以x-3/(x+1)≤-1
令t=x+1
t-1-3/t≤-1
t-3/t≤0
0<t≤√3或-√3≤t<0
-1<x≤√3-1或-√3-1≤x<-1

Answer 2

2^(x-3)/(x+1)≤1/2
2^(x-3)/(x+1)≤2^(-1)
2>1
所以
(x-3)/(x+1)≤-1
(x-3)/(x+1)+1≤0
(x-3+x+1)/(x+1)≤0
(x-1)/(x+1)≤0
(x-1)(x+1)≤0
-1<x≤1