Question

A、B、C、D、E、F为原子序数依次增大的短周期元素，已知A、B、E三种原子最外层有11个电子……

A、B、C、D、E、F为原子序数依次增大的短周期元素，已知A、B、E三种原子最外层有11个电子，且这3种元素的最高价氧化物的水化物两两皆能发生反应生成盐和水，C元素最外层电子比次外层电子少4，D元素原子次外层电子比最外层电子多3.
（1）写出下列元素符号：
A_______, B_______, C_______, D________, E________
(2)A与E两元素可形成化合物，用电子式表示其化合物的形成过程：
———————————————————————————————
（3）写出A、B两元素的最高价氧化物的水化物相互反应的化学方程式：
———————————————————————————————
（4）C、D、E的氢化物稳定性由强到弱依次为：（用化学式表示）
——————————————————

Answer 1

这是元素周期表模块常考的题型，推断题，要能从结构和性质两方面推断
A、B、E这3种元素的最高价氧化物的水化物两两皆能发生反应生成盐和水，短周期能符合的
A是钠，B是铝，C可能是硫或氯（因为能两两反应，所以有一个必须能形成两性氢氧化物，即铝）
钠最外层1个电子，铝3个电子，所以E最外层就是7个电子，为氯
C元素最外层电子比次外层电子少4，所以为2,8,4的电子排布，为硅
D元素原子次外层电子比最外层电子多3，所以为2,8,5的电子排布，为磷

Answer 2

1 Na Al Si P Cl Ar
2 (电子不知道怎么打，不好意思)
3 NaOH+Al(OH)3=NaAlO2+2H2O
4 HCl PH3 SiH4

Answer 3

二楼是正确的！ 电子式就Na的外围有一个电子然后加Cl外围七个电子,然后等于NaCl

Answer 4

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