Question

已知 △ABC的外接圆半径为R，且2R(sin^2A-sin^2C)=(√2a-b)sinB(其中a,b分别是A,B的对边），那么角C的大小

Answer 1

2R(sin^2A-sin^2C)=√2×2RsinAsinB-2RsinBsinB
sinAsinA-sinCsinC=√2×sinAsinB-sinBsinB
sinAsinA-sin(A+B)^2=√2×sinAsinB-sinBsinB
sinAsinA-sinAsinAcosBcosB-sinBsinBcosAcosA-2sinAcosAsinBcosB=√2×sinAsinB-sinBsinB
sinAsinA(1-cosBcosB)-sinBsinBcosAcosA-2sinAcosAsinBcosB=√2×sinAsinB-sinBsiinB
sinAsinAsinBsinB+sinBsinB(1-cosAcosA)-2sinAcosAsinBcosB=√2×sinAsinB
2sinAsinB(sinAsinB-cosAcosB-√2/2)=0
2sinAsinB[-cos(A+B)-√2/2]=0

因为sinA不等于0，sinB不等于0，
所以A+B=135º
所以C=45º