分式的加减计算： (1/x-y-x^2+y^2)-(1/1-x^2-2xy-y^2) 注：“/”指除号。
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1/(x-y-x^2+y^2)-1/(1-x^2-2xy-y^2)
=1/[(x-y)(1-x-y)]-1/[1-(x+y)^2]
=1/[(x-y)(1-x-y)]-1/[(1-x-y)(1+x+y)]
=[1+x+y-(x-y)]/[(x-y)(1-x-y)(1+x+y)]
=(1+2y)/[(x-y)(1-x-y)(1+x+y)]
=1/[(x-y)(1-x-y)]-1/[1-(x+y)^2]
=1/[(x-y)(1-x-y)]-1/[(1-x-y)(1+x+y)]
=[1+x+y-(x-y)]/[(x-y)(1-x-y)(1+x+y)]
=(1+2y)/[(x-y)(1-x-y)(1+x+y)]
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