已知sinx=1/3,sin(x+y)=1,则sin(2y+x)=
2个回答
2011-08-06
展开全部
一般这里的x,y都属于锐角
sin(x+y)=1
sin(2x+2y)=0 cos(2x+2y)=-1
sin(2y+x)=sin[(2x+2y)-x]
=sin(2x+2y)cosx-sinxcos(2x+2y)
=0-1/3*(-1)
=1/3
sin(x+y)=1
sin(2x+2y)=0 cos(2x+2y)=-1
sin(2y+x)=sin[(2x+2y)-x]
=sin(2x+2y)cosx-sinxcos(2x+2y)
=0-1/3*(-1)
=1/3
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