Question

编程：求下列分段函数的值：当x≥0时，y=2x+1; 当x<0时，y=2x-1

Answer 1

#include<stdio.h>
void main()
{
float x,y;
printf("请输入x的值:");
scanf("%f",&x);
if(x<0)
y=2*x-1;
else
y=2*x+1;
printf("x=%f,y=%.2f\n",x,y);
}

Answer 2

#include<stdio.h>
main(){
float x,y;
scanf("%f",&x);
if(x>=0)y=2*x+1;
else y=2*x-1;
printf("%.2f",y);
}
/*通过vc++6.0编译*/

Answer 3

VB解答
Private Sub Command1_Click()
Dim x, y As Single
x = Text1.Text
If x >= 0 Then
y = 2 * x + 1
Else
y = 2 * x - 1
End If

Print "y="; y
End Sub

Answer 4

double valueOfY(double x){
if(x>=0){
return x*2+1;
}else if(x<0){
return x*2-1;
}
}