Question

根号下x+1 减 根号下y-1=5 x+y=37 解方程组

Answer 1

根号下（x+1） 减 根号下（y-1）=5
等号两边都平方
x+1-2×根号下（x+1）×根号下（y-1）+y-1=25
x+y=25+2×根号下（x+1）×根号下（y-1）
x+y=37
25+2×根号下（x+1）×根号下（y-1）=37
2×根号下（x+1）×根号下（y-1）=12
根号下（x+1）×根号下（y-1）=6
两边都平方
（x+1）（y-1）=36
x+1=36/(y-1)
x=36/(y-1)-1
x=37-y
37-y=36/(y-1)-1
y^2-39y+74=0
(y-37)(y-2)=0
得出：y1=37 y2=2那么：x1=0 x2=35

Answer 2

设 x+1 = u^2, y-1=v^2 ，
=> u-v=5, u^2+v^2=37
=>u=6,v=1
=> x= 35, y=2

Answer 3

y=2 x=35