Question

5(x-1)的平方-2(x+3)的平方=(x-2)(3x+6)-12x

要详细的过程

Answer 1

5(x-1)^2-2(x+3)^2=(x-2)(3x+6)-12x
5x^2-10x+5-2x^2-24x-18=3x^2-12-12x
3x^2-34x+13=3x^2-12x-12
34x-12x=13+12
22x=25
x=25/22

Answer 2

解：
5(x²-2x+1)-2(x²+6x+9)=3(x-2)(x+2)-12x
5x²-10x+5-2x²-12x-18=3x²-12-12x
-10x=1
x=-1/10

Answer 3

5(x-1)²-2(x+3)²=(x-2)(3x+6)-12x
解：
5(x²-2x+1)-2(x²+6x+9)=3(x-2)(x+2)-12x
5x²-10x+5-2x²-12x-18=3x²-12-12x
-10x=1
x=-1/10
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Answer 4

5（x^2-2x+1）-2(x^2+6x+9)=3x^2-6x+6x-12-12x
5x^2-10x+5-2x^2-12x-18=3x^2-12-12x
-10x=1
x=-1/10

Answer 5

5(x^2-2x+1)-2(x^2+6x+9)=3x^2-22x-13 = 3x^2-12-12x ===>x=-0.1