
(1)计算(-3)2+(π-4)0-(-12)-1;(2)化简:(1?1a+1)÷a2?aa+1
(1)计算(-3)2+(π-4)0-(-12)-1;(2)化简:(1?1a+1)÷a2?aa+1....
(1)计算(-3)2+(π-4)0-(-12)-1;(2)化简:(1?1a+1)÷a2?aa+1.
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(1)原式=9+1-
=10+2
=12;
(2)原式=(
-
)÷
=(
-
)?
=
?
=
.
1 | ||
?
|
=10+2
=12;
(2)原式=(
a+1 |
a+1 |
1 |
a+1 |
a(a?1) |
a+1 |
=(
a+1 |
a+1 |
1 |
a+1 |
a+1 |
a(a?1) |
=
a |
a+1 |
a+1 |
a(a?1) |
=
1 |
a?1 |
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