
这个程序哪里有问题啊,在vc2010中生成不了.exe文件
#include<stdion.h>#include<math.h>floatf(floatx){floaty;y=((x-5.0)*x+16.0)*x-80.0;ret...
#include<stdion.h>
#include<math.h>
float f(float x)
{
float y;
y=((x-5.0)*x+16.0)*x-80.0;
return (y);
}
float xpoint(float x1,float x2)
{
float y;
y=(x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));
return (y);
}
float root(float x1,float x2)
{
float x,y,y1;
y1=f(x1);
do
{
x=xpoint(x1,x2);
y=f(x);
if(y*y1>0)
{
x1=x;
y1=y;
}
else x2=x;
}while(fabs(y)>1e-4)
return (x);
}
void main()
{
float x1,x2,f1,f2,x;
do
{
printf("input x1,x2:\n");
scanf("%f,%f",&x1,&x2);
f1=f(x1);
f2=f(x2);
}while(f1*f2>=0)
x=root(x1,x2);
printf("A root of equation is %8.4f\n",x);
} 展开
#include<math.h>
float f(float x)
{
float y;
y=((x-5.0)*x+16.0)*x-80.0;
return (y);
}
float xpoint(float x1,float x2)
{
float y;
y=(x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));
return (y);
}
float root(float x1,float x2)
{
float x,y,y1;
y1=f(x1);
do
{
x=xpoint(x1,x2);
y=f(x);
if(y*y1>0)
{
x1=x;
y1=y;
}
else x2=x;
}while(fabs(y)>1e-4)
return (x);
}
void main()
{
float x1,x2,f1,f2,x;
do
{
printf("input x1,x2:\n");
scanf("%f,%f",&x1,&x2);
f1=f(x1);
f2=f(x2);
}while(f1*f2>=0)
x=root(x1,x2);
printf("A root of equation is %8.4f\n",x);
} 展开
展开全部
#include<stdion.h> //你确定不是 #include<stdio.h>
30行缺个分号,改成下面应该就能编译了
#include<stdio.h>
#include<math.h>
float f(float x)
{
float y;
y=((x-5.0)*x+16.0)*x-80.0;
return (y);
}
float xpoint(float x1,float x2)
{
float y;
y=(x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));
return (y);
}
float root(float x1,float x2)
{
float x,y,y1;
y1=f(x1);
do
{
x=xpoint(x1,x2);
y=f(x);
if(y*y1>0)
{
x1=x;
y1=y;
}
else x2=x;
}while(fabs(y)>1e-4);
return (x);
}
int main()
{
float x1,x2,f1,f2,x;
do
{
printf("input x1,x2:\n");
scanf("%f,%f",&x1,&x2);
f1=f(x1);
f2=f(x2);
}while(f1*f2>=0);
x=root(x1,x2);
printf("A root of equation is %8.4f\n",x);
return 0;
}
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