函数f(x)等于根号下三cos平方二分之一x+sin1/2xcos1/2x 2)
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f(x)=√3(cos(x/2))^2+sin(x/2)cos(x/2)
=(√3/2)(cosx+1)+(1/2)sinx
=sin(π/6+x)+√3/2
f(x)=3/5+√3/2
sin(π/6+x)=3/5
π/6<x<π/3, π/3<(π/6+x)<π/2 cos(π/6+x)>0
cos(π/6+x)=4/5
sinx=sin(π/6+x-π/6)=sin(π/6+x)cos(π/6)-cos(π/6+x)sin(π/6)
=(3/5)(√3/2) -(4/5)(1/2)
=(3√3-4)/10
cos2x=1-2(sinx)^2=1-2*(3√3-4)^2/100=1-(43-24√3)/50=(7+24√3)/50
=(√3/2)(cosx+1)+(1/2)sinx
=sin(π/6+x)+√3/2
f(x)=3/5+√3/2
sin(π/6+x)=3/5
π/6<x<π/3, π/3<(π/6+x)<π/2 cos(π/6+x)>0
cos(π/6+x)=4/5
sinx=sin(π/6+x-π/6)=sin(π/6+x)cos(π/6)-cos(π/6+x)sin(π/6)
=(3/5)(√3/2) -(4/5)(1/2)
=(3√3-4)/10
cos2x=1-2(sinx)^2=1-2*(3√3-4)^2/100=1-(43-24√3)/50=(7+24√3)/50
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问的是COS2ｘ啊
追答
cos2x=1-2(sinx)^2
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