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(x+y)^2(x-y)^3-(-x-y)^3(y-x)^2
=(x+y)^2(x-y)^3+(x+y)^3(y-x)^2
=(x+y)^2(x-y)^3+(x+y)^3(x-y)^2 ①
接着提取公因式(x+y)^2和(x-y)^2
①式就=(x+y)^2(x-y)^2(x-y+x+y)=2x(x+y)^2(x-y)^2 =2x(x²-y²)²
=(x+y)^2(x-y)^3+(x+y)^3(y-x)^2
=(x+y)^2(x-y)^3+(x+y)^3(x-y)^2 ①
接着提取公因式(x+y)^2和(x-y)^2
①式就=(x+y)^2(x-y)^2(x-y+x+y)=2x(x+y)^2(x-y)^2 =2x(x²-y²)²
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你好!
(x+y)^2(x-y)^3-(-x-y)^3(y-x)^2
=(x+y)^2(x-y)^3+(x+y)^3(x-y)^2
=(x+y)^2(x-y)^2[(x-y)+(x+y)]
=(x+y)^2(x-y)^2(2x)
=2x(x+y)^2(x-y)^2
祝你学习进步O(∩_∩)O哈!
(x+y)^2(x-y)^3-(-x-y)^3(y-x)^2
=(x+y)^2(x-y)^3+(x+y)^3(x-y)^2
=(x+y)^2(x-y)^2[(x-y)+(x+y)]
=(x+y)^2(x-y)^2(2x)
=2x(x+y)^2(x-y)^2
祝你学习进步O(∩_∩)O哈!
追问
(x+y)^2(x-y)^3-(-x-y)^3(y-x)^2怎么到=(x+y)^2(x-y)^3+(x+y)^3(x-y)^2的
谢谢 你两次帮我回答了问题 麻烦你再帮我回答一下我的追问
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(x+y)^2(x-y)^3-(-x-y)^3(y-x)^2
=(x+y)^2(x-y)^3-(-1)^3(-1)^2(x+y)^3(x-y)^2
=(x+y)^2(x-y)^3+(x+y)^3(x-y)^2
=(x+y)^2(x-y)^2[(x-y)+(x+y)]
=2x(x+y)²(x-y)²
=(x+y)^2(x-y)^3-(-1)^3(-1)^2(x+y)^3(x-y)^2
=(x+y)^2(x-y)^3+(x+y)^3(x-y)^2
=(x+y)^2(x-y)^2[(x-y)+(x+y)]
=2x(x+y)²(x-y)²
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解:﹙x+y﹚²﹙x-y﹚³-﹙﹣x-y﹚³﹙y-x﹚²
=﹙x+y﹚²﹙x-y﹚³+﹙x-y﹚²﹙x+y﹚³
=﹙x+y﹚²﹙x-y﹚²﹙x-y+x+y﹚
=2x﹙x+y﹚²﹙x-y﹚².
=﹙x+y﹚²﹙x-y﹚³+﹙x-y﹚²﹙x+y﹚³
=﹙x+y﹚²﹙x-y﹚²﹙x-y+x+y﹚
=2x﹙x+y﹚²﹙x-y﹚².
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