Question

HttpWebRequest发送post请求时有多个参数如何处理

Answer 1

asmx代码

<%@ WebService Language="C#" Class="Service1" %>

using System;
using System.Web;
using System.Web.Services;
using System.Web.Services.Protocols;

[WebService(Namespace = "http://tempuri.org/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
//若要允许使用 ASP.NET AJAX 从脚本中调用此 Web 服务，请取消对下行的注释。
// [System.Web.Script.Services.ScriptService]
public class Service1 : System.Web.Services.WebService {

[WebMethod]
public string doSearch(String p1,String p2,String p3)
{
return "Hello World" + p1 + p2 + p3;
}
}

winform代码

private void button1_Click(object sender, EventArgs e)
{
string strURL = "http://localhost:2852/WebSite1/Service1.asmx/doSearch";
System.Net.HttpWebRequest request;
request = (System.Net.HttpWebRequest)HttpWebRequest.Create(strURL);
//Post请求方式
request.Method = "POST";
// 内容类型
request.ContentType = "application/x-www-form-urlencoded";

//这是原始代码：
string paraUrlCoded = "p1=x&p2=y&p3=测试的中文";
byte[] payload;
//将URL编码后的字符串转化为字节
payload = System.Text.Encoding.UTF8.GetBytes(paraUrlCoded);
//设置请求的 ContentLength
request.ContentLength = payload.Length;
//获得请 求流
Stream writer = request.GetRequestStream();
//将请求参数写入流
writer.Write(payload, 0, payload.Length);
// 关闭请求流
writer.Close();
System.Net.HttpWebResponse response;
// 获得响应流
response = (System.Net.HttpWebResponse)request.GetResponse();
System.IO.Stream s;
s = response.GetResponseStream();
XmlDocument d = new XmlDocument();
d.Load(s);
MessageBox.Show(d.DocumentElement.InnerText);

}