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(1)
consider : a^3 -b^3 = (a-b)(a^2+ ab +b^2 )
lim(x->+∞)√x . (x^(1/3) -1 )
=lim(x->+∞)√x . ( x -1 ) / ( x^(2/3) + x^(1/3) +1 )
=lim(x->+∞) ( 1 - x^(-1) ) / [ x^(-5/6) + x^(-4/3) +x^(-3/2) ]
=0
consider : a^3 -b^3 = (a-b)(a^2+ ab +b^2 )
lim(x->+∞)√x . (x^(1/3) -1 )
=lim(x->+∞)√x . ( x -1 ) / ( x^(2/3) + x^(1/3) +1 )
=lim(x->+∞) ( 1 - x^(-1) ) / [ x^(-5/6) + x^(-4/3) +x^(-3/2) ]
=0
追问
是x的1/x次幂
不是1/3次幂啊。。
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