Question

C#如何遍历XML中的内容并输出到datagardview中？

最终的效果如图中所示。
XML文件如下
<?xml version="1.0" encoding="utf-8" ?>
<root>
<location name="美国">
<server name="一号服务器" ipaddr="d1.cctv.com"/>
<server name="二号服务器" ipaddr="d2.cctv.com"/>
<server name="三号服务器" ipaddr="d3.cctv.com"/>
<server name="四号服务器" ipaddr="las.cctv.com"/>
<server name="五号服务器" ipaddr="udp53.cctv.com"/>
<server name="六号服务器|不限流量" ipaddr="d6.cctv.com"/>
<server name="七号服务器|不限流量" ipaddr="d9.cctv.com"/>
</location>
<location name="亚洲">
<server name="香港" ipaddr="hk1.cctv.com"/>
<server name="日本" ipaddr="jp1.cctv.com"/>
</location>
</root>

Answer 1

addInList = new List<AddIn>();
if (!File.Exists(Config_File))
{
System.Console.WriteLine("不存在配置文件");
return;
}

try
{
XmlDocument document = new XmlDocument();

document.Load(Config_File);

XmlNode root = document.DocumentElement;

//取得节点列表
XmlNodeList nodeList = root.ChildNodes;

foreach (XmlNode node in nodeList)
{
if (node.Name == "Addin")
{
AddIn addin = new AddIn();

XmlNodeList nodeListdetail = node.ChildNodes;
foreach (XmlNode nodedetail in nodeListdetail)
{
if (nodedetail.Name.Equals("FriendlyName"))
{
addin.FriendlyName = nodedetail.InnerText;
}
else if (nodedetail.Name.Equals("Description"))
{
addin.Description = nodedetail.InnerText;
}
else if (nodedetail.Name.Equals("Assembly"))
{
addin.Assembly = nodedetail.InnerText;
}
else if (nodedetail.Name.Equals("FullClassName"))
{
addin.FullClassName = nodedetail.InnerText;
}
else if (nodedetail.Name.Equals("BeforeLogin"))
{
addin.BeforeLogin = nodedetail.InnerText;
}
else if (nodedetail.Name.Equals("AfterLogin"))
{
addin.AfterLogin = nodedetail.InnerText;
}
else if (nodedetail.Name.Equals("ExitApp"))
{
addin.ExitApp = nodedetail.InnerText;
}
}
addInList.Add(addin);
}else if (node.Name == "LoginForm")
{
XmlNodeList nodeListdetail = node.ChildNodes;
foreach (XmlNode nodedetail in nodeListdetail)
{
if (nodedetail.Name.Equals("Assembly"))
{
LoginFormAssembly = nodedetail.InnerText;
}
else if (nodedetail.Name.Equals("FullClassName"))
{
LoginFormClassName = nodedetail.InnerText;
}
}
}
else if (node.Name == "MainForm")
{
XmlNodeList nodeListdetail = node.ChildNodes;
foreach (XmlNode nodedetail in nodeListdetail)
{
if (nodedetail.Name.Equals("Assembly"))
{
MainFormAssembly = nodedetail.InnerText;
}
else if (nodedetail.Name.Equals("FullClassName"))
{
MainFormClassName = nodedetail.InnerText;
}
}
}
}
}

希望你看得懂..

Answer 2

浏览到一个网址就是解决你这个问题的：http://tuibianzhilv001.blog.163.com/blog/static/167563877201062024821564/
进去看一下吧！

Answer 3

上面写的 也没有如何加载到datagridview中啊

Answer 4

ren wu d