Question

C语言计算s = 2^2 + 4^2 + 6^2 + … + 100^2 用for while do-while 语句

Answer 1

Private Sub Command1_Click()

s = 0

For i = 2 To 100 Step 2

s = s + i * i

Next i

Print "方法1：s="; s

Print

s = 0: i = 2

While i < 101

s = s + i * i

i = i + 2

Wend

Print "方法2：s="; s

Print

s = 0: i = 2

Do

s = s + i * i

i = i + 2

Loop While i < 101

Print "方法3：s="; s  

End Sub

Answer 2

int sum = 0，i = 2;
while (i <= 100)
{
	sum += i*i;
	i *= 2;
}
//或者是
int sum = 0，i = 2;
do
{
	sum += i*i;
	i *= 2;
} while (i <= 100);

Answer 3

#include <stdio.h>
int main(int argc,char *argv[]){
    int s,i;
    for(s=i=0;i<=100;s+=i*i,i+=2);
    printf("The result is %d\n",s);
    return 0;
}