Question

是关于整式的，1、如果多项式（a-2)x的4次方-二分之一x的b次方+x的²-3是x的三次多项式，则

1、如果多项式（a-2)x的4次方-二分之一x的b次方+x的²-3是x的三次多项式，则

A：a=0,b=3 B：a=1,b=3 C: a=2,b=3 D: a=2,b=1

请各位会解答的尽量帮我解疑（请大家说出解题方法），我谢谢你们了

Answer 1

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Answer 2

因为是三次，所以x的四次方不存在，a-2等于0，a=2，最高次是三次，所以b=3，选c

Answer 3

x的三次多项式，则说明最高次为3次，所以a=2，b=3 ，只有这样才成立！

Answer 4

C: a=2,b=3
是x的三次多项式，所以四次项系数为0，后三项中缺少三次项，所以b=3