Question

因式分解：x²-2xy+y²+10x-10y+25

Answer 1

双十字法：
x²-2xy+y²+10x-10y+25
x -y 5
x -y 5
原式=(x-y+5)^2

Answer 2

x²-2xy+y²+10x-10y+25
=(x²-2xy+y²)+(10x-10y)+25
=(x-y)²+10(x-y)+5²
=(x-y+5)²

Answer 3

很简单的因式分解法
x²-2xy+y²+10x-10y+25
=(x²-2xy+y²)+(10x-10y)+25
=(x-y)²+10(x-y)+5²
=(x-y+5)²

Answer 4

x²-2xy+y²+10x-10y+25
=(x-y)²+10(x-y)+25
=(x-y+5)²

Answer 5

(x-y)2+5(x-y+5)