Question

高数。定积分。第7题怎么做?

Answer 1

有点模糊，不过不打紧

Answer 2

换元t=√x，dx=2tdt
=∫(0到2)2(t²+3)/(2-t²)dt
=∫10/(2-t²)-2dt
=10/2√2∫1/(√2+t)+1/(√2-t)-2dt
=(5/√2)(ln(√2+t)-ln(√2-t))-2t