Question

数学题(1)38.5²-36.5²(2)（2x-3y-1）（2x+3y+1）（3+1）（3^2+1）（3^4+1）(3^8+1)(3^16+1)

抱歉是第一题38.5²-36.5² 第二题（2x-3y-1）（2x+3y+1）第三题（3+1）（3^2+1）（3^4+1）(3^8+1)(3^16+1)第四题2003^2-3001^2

Answer 1

1.
38.5^2-36.5^2
=(38.5+36.5)(38.5-36.5)
=75*2
=150
2.
(2x-3y-1)(2x+3y+1)
=[2x-(3y+1)][2x+(3y+1)]
=4x^2-(3y+1)^2
=4x^2-(9y^2+6y+1)
=4x^2-9y^2-6y-1
3.
(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^4-1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^8-1)(3^8+1)(3^16+1)
=(1/2)(3^16-1)(3^16+1)
=(1/2)(3^32-1)
=3^32/2-1/2

Answer 2

(1).38.5²-36.5²=(38.5+36.5)(38.5-36.5)=75*2=150
(2).（2x-3y-1）（2x+3y+1）=(2x-(3y+1))(2x+(3y+1))=(2x)²-(3y+1)²=4x²-9y²-6y+1
(3).（3+1）（3^2+1）（3^4+1）(3^8+1)(3^16+1)
=0.5(3-1)（3+1）（3^2+1）（3^4+1）(3^8+1)(3^16+1)
=0.5(3²-1)(3²+1)（3^4+1）(3^8+1)(3^16+1)
=0.5(3^4-1)(3^4+1)(3^8+1)(3^16+1)
=0.5(3^8-1)(3^8+1)(3^16+1)
=0.5(3^16-1)(3^16+1)
=0.5(3^32-1)

Answer 3

（38.5-36.5）*（38.5+36.5）=150
=4x²-(3y+1)²=4x²-9y²-6y-1
第三题我只会直接用计算机算

Answer 4

1、（38,5-36.5）*（38.5+36.5）=150
2、[2x-(3y+1）]*[2x+(3y+1)]=4x^2-(3y+1)^2
3、92651009442520

Answer 5

1：150
2：4x^2-9y^2-6y-1
3：9.265100944×10的14次方