Question

简单计算题

解救啊~~~求 简 便 算 法 (∩_∩) (∩_∩)
x/(x-3)-5x/(x^2-x-6)

Answer 1

x/(x-3)-5x/(x^2-x-6)
=x/(x-3)-5x/(x-3)(x+2)
=x(x+2)/(x-3)(x+2)-5x/(x-3)(x-+2)
=(x²+2x-5x)/（x-3)(x+2)
=x(x-3)/(x-3)(x+2)
=x/(x+2)

Answer 2

等于 ？？？？？？？？？？？？？？

Answer 3

原式=x/(x-3)-5x/[(x-3)(x+2)]=x(x+2)/[(x-3)(x+2)]-5x/[(x-3)(x+2)]
=[x(x+2)-5x]/[(x-3)(x+2)]
=(x²+2x-5x)/[(x-3)(x+2)]
=(x²-3x)/[(x-3)(x+2)]
=x(x-3)/[(x-3)(x+2)]
=x/(x+2)

Answer 4

原式=x/(x-3)-5x/((x+2)*(x-3))
=(x*(x+2)-5x)/((x-3)*(x+2))
=(x^2-3x)/((x-3)*(x+2))
=x*(x-3)/((x-3)*(x+2))
=x/(x+2)