Question

化简求值b/(a-b)-b³/(a³-2a²b+ab²)÷(ab+b²)/(a²-b²)，其中a=-2,b=3

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Answer 1

原式=b/(a-b)-b³/a(a-b)²÷[b(a+b)/(a+b)(a-b)]}
=b/(a-b)-b³/a(a-b)²×[(a-b)/b]
=b/(a-b)-b²/a(a-b)
=(ab-b²)/a(a-b)
=b/a
当a=-2,b=3时
原式=b/a=3/(-2)=-3/2