Question

C语言编程：用while循环求1+1/3+1/5+1/7+1/9+...+1/(2n-1)的值。n由键盘输入，正整数，咋写？

Answer 1

代码文本：

#include "stdio.h"

int main(int argc,char *argv[]){ 

int n,m;

double s;

printf("Enter n(int n>0)...\nn=");

if(scanf("%d",&n)==1 && n>0){

printf("s(%d) = ",n);

s=m=0;

while(n--)

s+=1.0/(++m)++;

printf("%f\n",s);

}

else

printf("Input error, exit...\n");

return 0;

}