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先化简,再求值:(x-2)/(x^2-1)×(x^2+2x+1)/(x^2-x-2),其中,x=-2
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解答:
(x-2)/(x^2-1)*(x^2+2x+1)/(x^2-x-2)
=(x-2)/[(x+1)(x-1)*(x+1)^2/[(x-2)(x+1)]
=1/(x-1)=1/(-2-1)=-1/3
(x-2)/(x^2-1)*(x^2+2x+1)/(x^2-x-2)
=(x-2)/[(x+1)(x-1)*(x+1)^2/[(x-2)(x+1)]
=1/(x-1)=1/(-2-1)=-1/3
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