Question

请问如何为动态生成的ImageButton添加Click事件？

我的代码是这样的：
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
image();
}
}
public void image()
{
Class c = new Class();
string sql = "select * from Image";
DataSet ds = c.search(sql);
//将文件保存到文件夹，然后在读取
int i;
for (i = 0; i < ds.Tables[0].Rows.Count; i++)
{
ImageButton imgbtn= new ImageButton();
imgbtn.ID = i.ToString();
imgbtn.Width = Unit .Parse ("185px");
imgbtn.Height = Unit.Parse("100px");
imgbtn.ImageUrl = ds.Tables[0].Rows[i]["PathName"].ToString();
imgbtn.Click += new ImageClickEventHandler(imgbtn_Click);
this.div.Controls.Add(imgbtn);
}
while (i <5)
{
ImageButton imgbtn = new ImageButton();
imgbtn.ID = i.ToString();
imgbtn.Width = Unit.Parse("185px");
imgbtn.Height = Unit.Parse("100px");
imgbtn.ImageUrl = "Images/招租.gif";
this.div.Controls.Add(imgbtn);
i++;
}
}
protected void imgbtn_Click(object sender, System.Web.UI.ImageClickEventArgs e)
{
ImageButton ib = (ImageButton)sender;
Class c = new Class();
string sql = "select * from Image where PathName='" + ib.ImageUrl.ToString () + "'";
DataSet ds = c.search(sql);
Response.Redirect(ds.Tables[0].Rows[0]["Name"].ToString());
}

Answer 1

把这个方法image()通过后台代呈现形成HTML代码在前台显示，后台事件不变！

追问

呵呵，不太明白你的意思，能不能具体点，谢谢

Answer 2

这样有问题么？

追问

点击之后没反应……