Question

avr的编译问题

问题：我用的是avr的MEGA128，编辑后出现以下提示，请教是什么意思

Error[e16]: Segment NEAR_Z (size: 0x91d align: 0) is too long for segment definition. At least 0xeb more bytes needed. The problem occurred while processing the segment placement command "-Z(DATA)NEAR_I,NEAR_Z=_..X_SRAM_BASE-_..X_SRAM_END,_..X_EXT_SRAM_BASE-_..X_EXT_SRAM_END", where at the moment of placement the available memory ranges were "8bc-10ff"

我程序中有
DispStr(" ",20);

void DispStr( unsigned char* str, unsigned char sit )
{//把传送来字符串显示在指定位置上
unsigned char chr;

if( sit >= 40 )
sit = 0; //显示位置出错，设为0
while( ( chr = *str++ ) != '\0' )
{
DispByte( chr, sit );
sit++;
}
}

当我把DispStr(" ",20);
改为
for( i=20; i<40; i++ )
DispStr("*",i);
编译提示中的At least 0xeb more bytes needed.
就变成At least 0xd9 more bytes needed.
我用的是ew23编译的

Answer 1

感觉是你的指针映射地址溢出，
如果想显示空格可以这样用
unsigned char a[20]=" ";
DispStr(a,20);

Answer 2

alone6230回答正确