Question

曲线c的参数方程是x=2(t+1/t)与y=3(t-1/t)的普通方程

Answer 1

x=2(t+1/t)与y=3(t-1/t)
x/2=t+1/t,y/3=t-1/t
两式两边分别平方得
x^2/4=t^2+1/t^2+2,y^2/9=t^2+1/t^2-2
两式相减得
x^2/4-y^2/9=4

Answer 2

②两式平方相加，得到x^2/(t 1/t) ^2 y^2/(t-1/t) ^2=1 其中(t 1/t) ^2-(t-1/t) ^2=4

Answer 3

x=2(t+1/t)与y=3(t-1/t)
x/2=t+1/t,y/3=t-1/t
两式两边分别平方得
x^2/4=t^2+1/t^2+2,y^2/9=t^2+1/t^2-2
两式相减得
x^2/4-y^2/9=4 同意“午后蓝山”的做法！