关于gmat数学题,求解答过程
Inthefractionx/y,wherexandyarepositiveintegers,whatisthevalueofy?(1)leastcommondenomi...
In the fraction x/y,where x and y are positive integers,what is the value of y?
(1)least common denominatro of x/y and 1/3 is 6
(2)x=1
答案E
For manufacture M,the cost C of producing x units of its units of its product per month is given by C=kx+t,where C is in dollars and k and t are constans.Last month, if Manufacture M produced 1000 units of its product and sold all the units for k+60 dollars each ,whatwas Manufacturer M's gross profit on the 1000 units?
(1)Last month, Manufacturer m's revenue from the sale of the 1000 units was$150000
(2)Manufacturer m's cost of producing 500 units in a month is $45000 less than its cost of producing 1000 units in a month
答案E 展开
(1)least common denominatro of x/y and 1/3 is 6
(2)x=1
答案E
For manufacture M,the cost C of producing x units of its units of its product per month is given by C=kx+t,where C is in dollars and k and t are constans.Last month, if Manufacture M produced 1000 units of its product and sold all the units for k+60 dollars each ,whatwas Manufacturer M's gross profit on the 1000 units?
(1)Last month, Manufacturer m's revenue from the sale of the 1000 units was$150000
(2)Manufacturer m's cost of producing 500 units in a month is $45000 less than its cost of producing 1000 units in a month
答案E 展开
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第一题:1、2条件均无法独立求解,两个条件联立,也只能知道Y可以取1、2、3、6(我认为应该考虑1/3=2/6),无法确定唯一的Y。选E。
第二题:成本C和生产数量X满足公式C=kx+t。若上个月X=1000,售价为 K+60(单价), 那么这1000数量的净利润是多少?
(1)上个月,从1000数量产品的收入是150000
150000=10000*(K+60)只能求出K,没有t, 无法计算C,也就无法计算净利润。
(2)说了一个cost的大小问题,生产500数量的COST比生产1000数量的COST少45000,(
500K+t)-(1000K+T)=45000 也只能求出K,同(1)。
(1)(2)联合之后,算来算去只能求出K,无法求解。所以选E。
第二题:成本C和生产数量X满足公式C=kx+t。若上个月X=1000,售价为 K+60(单价), 那么这1000数量的净利润是多少?
(1)上个月,从1000数量产品的收入是150000
150000=10000*(K+60)只能求出K,没有t, 无法计算C,也就无法计算净利润。
(2)说了一个cost的大小问题,生产500数量的COST比生产1000数量的COST少45000,(
500K+t)-(1000K+T)=45000 也只能求出K,同(1)。
(1)(2)联合之后,算来算去只能求出K,无法求解。所以选E。
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