
已知 (x-1)/(x+2)=(y-3)/(y-4) ,用含x的代数式表示y是
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(x-1)/(x+2)=(y-3)/(y-4)
(x-1)(y-4)=(x+2)(y-3)
xy-4x-y+4=xy-3x+2y-6
-3y=x-10
y=(10-x)/3
(x-1)(y-4)=(x+2)(y-3)
xy-4x-y+4=xy-3x+2y-6
-3y=x-10
y=(10-x)/3
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