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解:(1+y)^2-2x^2(1+y^2)+x^4(1-y)^2
=(1+y)^2-2 x^2(1+y)(1-y)+x^4(1-y)^2-4x^2y^2
=[(1+y)+x^2(1-y)]^2 -(2xy)^2
=[(1+y)+x^2(1-y)+2xy][(1+y)+x^2(1-y)-2xy]
=(1+y)^2-2 x^2(1+y)(1-y)+x^4(1-y)^2-4x^2y^2
=[(1+y)+x^2(1-y)]^2 -(2xy)^2
=[(1+y)+x^2(1-y)+2xy][(1+y)+x^2(1-y)-2xy]
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2011-09-10
展开全部
(1+y)^2-2x^2(1+y^2)+x^4(1-y)^2
=(1+y)^2-2 x^2(1+y)(1-y)+x^4(1-y)^2-4x^2y^2
=[(1+y)+x^2(1-y)]^2 -(2xy)^2
=[(1+y)+x^2(1-y)+2xy][(1+y)+x^2(1-y)-2xy]
=(1+y)^2-2 x^2(1+y)(1-y)+x^4(1-y)^2-4x^2y^2
=[(1+y)+x^2(1-y)]^2 -(2xy)^2
=[(1+y)+x^2(1-y)+2xy][(1+y)+x^2(1-y)-2xy]
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