Question

a^2-ab分之(a+b)^2除以[-(a-b)^2分之b^2+ab]

Answer 1

原式=(a+b)^2/a^2-ab乘以-(a-b)^2/b^2+ab
=(a+b)(a-b)/ab
=a^2-b^2/ab

Answer 2

(a+b)(a+b+2)+1=4
(a+b)²+2(a+b)+1=4
(a+b+1)²=4
a+b+1=±2
a+b=-1±2
a+b=1或-3