cos2a/sin(a-π/4) =-根号（2）/2,则cosa+sina的值为?
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cos2a/sin(a-π/4)=(2cos2a*cos(a-π/4)) /(2sin(a-π/4) cos(a-π/4))
cos2a/sin(a-π/4)=(2cos2a*cos(a-π/首告4)) /sin(2a-π/2)
cos2a/sin(a-π/4)=-(2cos2a*cos(a-π/4)) /cos2a
cos2a/sin(a-π/4)=-2*cos(a-π/罩碧4)
-2*cos(a-π/4) =-√2/2
cos(a-π/4) =√2/4
cosa*cos(π/物芹举4)+sina*sin(π/4)=√2/4
cosa+cosb=1/2
cos2a/sin(a-π/4)=(2cos2a*cos(a-π/首告4)) /sin(2a-π/2)
cos2a/sin(a-π/4)=-(2cos2a*cos(a-π/4)) /cos2a
cos2a/sin(a-π/4)=-2*cos(a-π/罩碧4)
-2*cos(a-π/4) =-√2/2
cos(a-π/4) =√2/4
cosa*cos(π/物芹举4)+sina*sin(π/4)=√2/4
cosa+cosb=1/2
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