Question

解不等式 x^2-x+2<0 (2x-3)/(x+1)<0 1/(x+2)<=3 2x^2+x<0 x^2-3x-18<=0 -x^2+x>=3x+1 x(x+9)>3(x-3)

(x+1)/(x-1)>=0
(3x+1)/(2x-1)<2
2/x>-1
(2x^2-x+1)/(2x+1)>0
x^2-2x>2x^2+2
x^2/2-x/3+1/5>=0
x^2-x+2<0
(2x-3)/(x+1)<0
1/(x+2)<=3
2x^2+x<0
x^2-3x-18<=0
-x^2+x>=3x+1
x(x+9)>3(x-3)

Answer 1

(x+1)/(x-1)>=0
x>1或者x<=-1

(3x+1)/(2x-1)<2
x>3或者x<1/2

2/x>-1
x<-2或者x>0

(2x^2-x+1)/(2x+1)>0
x>-1/2

x^2-2x>2x^2+2
无解

x^2/2-x/3+1/5>=0
任意解

x^2-x+2<0
无解

(2x-3)/(x+1)<0
-1<x<3/2

1/(x+2)<=3
x<-10/3或者x>-3

2x^2+x<0
-1/2<x<0

x^2-3x-18<=0
-3<=x<=6

-x^2+x>=3x+1
x= - 1

x(x+9)>3(x-3)
x≠ - 3

Answer 2

1

Answer 3

到底您是要解那些啊？全部？

Answer 4

x