Question

2的x次方展开为x-1的泰勒级数

Answer 1

2^x = 2 · 2^(x-1) = 2 · e^[(x-1)ln2]
= 2 ·∑<n=0, ∞>[(x-1)ln2]^n/n!
= 2 ·∑<n=0, ∞>(ln2)^n · (x-1)^n/n!