化简（初一数学题）要过程 (-2+x^2-3x^3)/(3x-1-2x^2)
展开全部
(-2+x^2-3x^3)/(3x-1-2x^2)
=-(-2+x^2-3x^3)/[-(3x-1-2x^2)]
=(3x^3-x^2-2)/(2x^2-3x+1)
=[(3x^3-3)-(x^2-1)]/[(2x^2-2)-(3x-3)]
=[3(x-1)(x^2+x+1)-(x+1)(x-1)]/[2(x+1)(x-1)-3(x-1)]
=(x-1)(3x^2+3x+3-x-1)/[(x-1)(2x+2-3)
=(3x^2+2x+2)/(2x-1)
=-(-2+x^2-3x^3)/[-(3x-1-2x^2)]
=(3x^3-x^2-2)/(2x^2-3x+1)
=[(3x^3-3)-(x^2-1)]/[(2x^2-2)-(3x-3)]
=[3(x-1)(x^2+x+1)-(x+1)(x-1)]/[2(x+1)(x-1)-3(x-1)]
=(x-1)(3x^2+3x+3-x-1)/[(x-1)(2x+2-3)
=(3x^2+2x+2)/(2x-1)
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
