先化简，再求值：x+1/x的平方+1÷（x+1）的三次方/x的四次方-1-(x-3)/(x+1),其中x=√3+1
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原式=(x+1)/(x²+1)×(x²+1)(x²-1)/(x+1)³-(x-3)/(x+1)
=(x²-1)/(x+1)²-(x-3)/(x+1)
=(x²-1-x²+2x+3)/(x+1)²
=2(x+1)/(x+1)²
=2/(x+1)
=2/(√3+1+1)
=4-2√3
=(x²-1)/(x+1)²-(x-3)/(x+1)
=(x²-1-x²+2x+3)/(x+1)²
=2(x+1)/(x+1)²
=2/(x+1)
=2/(√3+1+1)
=4-2√3
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