Question

我是matlab初学者 这个程序看不懂。。。第一个break有什么用啊第二个break不是一直都在运行吗？

鸡兔同笼问题啦
i=1;
while i>0
if rem(100-i*2,4)==0&(i+(100-i*2)/4)==36
break;
end
i=i+1;
n1=i;
n2=(100-2*i)/4;
break
end
fprintf('the number of chicken is %d.\n',n1);
fprintf('the number of rabbit is %d.\n',n2);

Answer 1

你的程序有问题，其有效成分仅仅如下：
i=1;
i=i+1;
n1=i;
n2=(100-2*i)/4;
fprintf('the number of chicken is %d.\n',n1);
fprintf('the number of rabbit is %d.\n',n2);
从上面看你并没有解决鸡兔同笼问题。
以下是按照你的程序修改的
clear;
clc;
i=1;
while i>0
if rem(100-i*2,4)==0&(i+(100-i*2)/4)==36
n1 = i;
n2 = (100-2*i)/4;
break;
end
i=i+1;
end
fprintf('the number of chicken is %d.\n',n1);
fprintf('the number of rabbit is %d.\n',n2);
结果：
the number of chicken is 22.
the number of rabbit is 14.
当然也可以不用这么复杂，可以采用以下程序：
[n1,n2] = solve('2*x+4*y-100','x+y-36'); %%%求解个方程组就成
fprintf('the number of chicken is %d.\n',double(n1));
fprintf('the number of rabbit is %d.\n',double(n2));