Question

请高手编写个通达信的简单公式：MACD红绿柱子背离

Answer 1

MACD顶底背离（同时包含KDJ背离，RSI背离）
公式如下：

DIFF:EMA(CLOSE,12) - EMA(CLOSE,26);
DEA:EMA(DIFF,9);
MACD:2*(DIFF-DEA),COLORSTICK;
A1:=BARSLAST(REF(CROSS(DIFF,DEA),1));
B1:=REF(C,A1+1)>C AND REF(DIFF,A1+1)<DIFF AND CROSS(DIFF,DEA);
A2:=BARSLAST(REF(CROSS("KDJ.K"(9,3,3),"KDJ.D"(9,3,3)),1));
B2:=REF(C,A2+1)>C AND REF("KDJ.K"(9,3,3),A2+1)<"KDJ.K"(9,3,3) AND CROSS("KDJ.K"(9,3,3),"KDJ.D"(9,3,3));
A3:=BARSLAST(REF(CROSS("RSI.RSI1"(6,12,24),"RSI.RSI2"(6,12,24)),1));
B3:=REF(C,A3+1)>C AND REF("RSI.RSI1"(6,12,24),A3+1)<"RSI.RSI1"(6,12,24) AND CROSS("RSI.RSI1"(6,12,24),"RSI.RSI2"(6,12,24));
C1:=BARSLAST(REF(CROSS(DEA,DIFF),1));
D1:=REF(C,C1+1)<C AND REF(DIFF,C1+1)>DIFF AND CROSS(DEA,DIFF);
C2:=BARSLAST(REF(CROSS("KDJ.D"(9,3,3),"KDJ.K"(9,3,3)),1));
D2:=REF(C,C2+1)<C AND REF("KDJ.K"(9,3,3),C2+1)>"KDJ.K"(9,3,3) AND CROSS("KDJ.D"(9,3,3),"KDJ.K"(9,3,3));
C3:=BARSLAST(REF(CROSS("RSI.RSI2"(6,12,24),"RSI.RSI1"(6,12,24)),1));
D3:=REF(C,C3+1)<C AND REF("RSI.RSI1"(6,12,24),C3+1)>"RSI.RSI1"(6,12,24) AND CROSS("RSI.RSI2"(6,12,24),"RSI.RSI1"(6,12,24));
MACD底背:IF(B1>0,-0.1,0),COLORRED,POINTDOT;
KDJ底背:IF(B2>0,-0.1,0),COLORFF00FF,POINTDOT;
RSI底背:IF(B3>0,-0.1,0),COLORYELLOW,POINTDOT;
MACD顶背:IF(D1>0,0.1,0),COLOR00FF00,POINTDOT;
KDJ顶背:IF(D2>0,0.1,0),COLORFFCC66,POINTDOT;
RSI顶背:IF(D3>0,0.1,0),COLORWHITE,POINTDOT;
STICKLINE(B1>0,-0.1,0,2,0),COLORRED;
STICKLINE(B2>0,-0.1,0,2,0),COLORFF00FF;
STICKLINE(B3>0,-0.1,0,2,0),COLORYELLOW;
STICKLINE(D1>0,0.1,0,2,0),COLOR00FF00;
STICKLINE(D2>0,0.1,0,2,0),COLORFFCC66;
STICKLINE(D3>0,0.1,0,2,0),COLORWHITE;

Answer 2

MACD顶底背离（同时包含KDJ背离，RSI背离）
公式如下：

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