Question

解方程: x-2y-z=0,x+3y+2z=1,x+4y+z=6

要用过程,还要详细

Answer 1

x-2y-z=0为1式,
x+3y+2z=1为2式,
x+4y+z=6为3式
2式-1式得5y+3z=1此设为4式；
3式-2式得y-z=5此设为6式；
4式+3倍6式得8y=16得y=2代入6式得z= -3，代入1式得x=1

Answer 2

x-2y-z=0
x+3y+2z=1
5y+3z=1
x+4y+z=6
3y+z=3
4y=8
y=2
x=1
z=-3