分解因式x^3-3x^2+4
3个回答
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1、x³+1-3x²+3 将4写成1+3
=(x+1)(x²-x+1)-3(x²-1)
=(x+1)(x²-x+1)-3(x+1)(x-1)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
2、x³+x²-4x²+4 -3x²=x²-4x²
=x²(x+1)-4(x+1)(x-1)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
3、x³-2x²-x²+4 -3x²=-2x²-x²
=x²(x-2)-(x+2)(x-2)
=(x-2)(x²-x-2)
=(x-2)(x-2)(x+1)
=(x-2)²(x+1)
4、x³-8-3x²+12
=(x-2)(x²+2x+4)-3(x+2)(x-2)
=(x-2)(x²-x-2)
=(x-2)²(x+1)
=(x+1)(x²-x+1)-3(x²-1)
=(x+1)(x²-x+1)-3(x+1)(x-1)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
2、x³+x²-4x²+4 -3x²=x²-4x²
=x²(x+1)-4(x+1)(x-1)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
3、x³-2x²-x²+4 -3x²=-2x²-x²
=x²(x-2)-(x+2)(x-2)
=(x-2)(x²-x-2)
=(x-2)(x-2)(x+1)
=(x-2)²(x+1)
4、x³-8-3x²+12
=(x-2)(x²+2x+4)-3(x+2)(x-2)
=(x-2)(x²-x-2)
=(x-2)²(x+1)
来自:求助得到的回答
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x^3-3x^2+4
=(x^3+x^2)-(4X^2-4)
=x^2(x+1)-4(x+1)(x-1)
=(x+1)(x^2-4x+4)
=(x+1)(x-2)²
=(x^3+x^2)-(4X^2-4)
=x^2(x+1)-4(x+1)(x-1)
=(x+1)(x^2-4x+4)
=(x+1)(x-2)²
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展开全部
x^3-3x^2+4
=x^3+x^2-4x^2+4
=x^2(x+1)-4(x-1)(x+1)
=(x-2)(x-2)(x+1)
=x^3+x^2-4x^2+4
=x^2(x+1)-4(x-1)(x+1)
=(x-2)(x-2)(x+1)
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