Question

因式分解 9(2a+3b)2-4(3a-2b)2

Answer 1

原式=[3(2a+3b)]²-[2(3a-2b)]²
=(6a+9b)²-(6a-4b)²
=(6a+9b+6a-4b)(6a+9b-6a+4b)
=13b(12a+5b)

Answer 2

9(2a+3b)2-4(3a-2b)2
=3^2(2a+3b)2-2^2(3a-2b)2
=(6a+9b)^2-(6a-4b)^2
=(6a+9b+6a-4b)(6a+9b-6a+4b)
=13b(12a+5b)