Question

因式分解

2x3+x2-8x-4
4a2+3b-3ab-4a
x3-x2y-xy2+y3
x2+ax-y2+ay
4x2-4xy-a2+y2
a3-3a2b+3ab2-b3
4p2-4pq+q2-qp+q
1+x2+x4
4x4+a4
3x3+2x-5

下列是完全平方是，求a
x2-12x+3a
9x2+axy+25y2

Answer 1

2x³+x²-8x-4
=2x³-8x+x²-4
=2x(x²-4)+(x²-4)
=(2x+1)(x+2)(x-2)
4a2+3b-3ab-4a
=4a²-3ab+3b-4a
=a(4a-3b)-(4a-3b)
=(a-1)(4a-3b)
x3-x2y-xy2+y3
=(x³+y³)-xy(x+y)
=(x+y)(x²+y²-xy)-xy(x+y)
=(x+y)(x²+y²-2xy)
=(x+y)(x-y)²
x2+ax-y2+ay
=x²-y²+a(x-y)
=(x+y)(x-y)+a(x-y)
=(x-y)(x+y+a)
4x2-4xy-a2+y2
=(2x-y)²-a²
=(2x-y+a)(2x-y-a)
a3-3a2b+3ab2-b3
=a³-b²-3ab(a-b)
=(a-b)(a²+b²+ab)-3ab(a-b)
=(a-b)(a²+b²-2ab)
=(a-b)(a-b)²
=(a-b)³
4p2-4pq+q2-qp+q
=(2p-q)²-q(p-1)
1+x2+x4
=x^4+2x²+1-x²
=(x²+1)-x²
=(x²+1+x)(x²+1-x)
4x4+a4
=4x4+a4+4x²a²-4x²a²
=(2x²+a²)²-4x²a²
=(2x²+a²+2ax)(2x²+a²-2ax)
3x3+2x-5
=3x3+2x-3-2
=3x3-3+2x-2
=3(x³-1)+2(x-1)
=3(x-1)(x²+1+x)+2(x-1)
=(x-1)(3x²+3+3x+2)
=(x-1)(3x²+3x+5)
下列是完全平方是，求a
x2-12x+3a不是
9x2+axy+25y2
a=30
9x2+30xy+25y²
=(3x+5y)²

Answer 2

（x-2)(x+2)(2x+1)
(4a-3b)(a-1)
(x-y)(x+y)(x-y)
(x-y+a)(x+y)
(2x-y+a)(2x-y-a)
看不懂：）
还是看不懂
做不出来
看不懂啊
做不出来
a=12
a=30
希望有帮助

追问

你好搞笑。。