Question

(2x^4-3x^3+16x^2-15x+15)除以(x^2-2x+3)

Answer 1

解：可以用除法竖式来做
2x² +x +12
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x²-2x+3 | 2x^4 -3x³ +16x² -15x +15
2x^4 -4x³ +6x²
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x³ +10x² -15x
x³ -2x² +3x
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12x² -18x +15
12x² -24x +36
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6x -21
所以
(2x^4-3x³+16x²-15x+15)÷(x²-2x+3)=商式为2x²+x+12， 余式为6x-21

Answer 2

=[(3X 4)(2X-5)/(X 2)(X-2)]*[(x-2)(x 1)]/3X(2x-5)]/[(3x 4)(x 1)]/x(x 2)=(3X 4)(2x-5)(x-2)(x 1)x(x 2)除以