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计算:
a-2b+ab-2ab
= a -2b+ab -ab -ab
= a - 2b - ab
= a - b ( 2 + a)
因为 a+b=0 ,
所以 a = - b
或 b = - a
分别代入原计算式得:
a-2b+ab-2ab
= a - b ( 2 + a)
= ( - b ) - b 〔 2 + ( - b )〕
= - 3 b + b ^2
= b ^2 - 3 b
或:
a-2b+ab-2ab
= a - b ( 2 + a)
= a - ( - a) ( 2 + a)
= a + 2a + a^2
= 3a + a ^2
= a ^2 + 3a
a-2b+ab-2ab
= a -2b+ab -ab -ab
= a - 2b - ab
= a - b ( 2 + a)
因为 a+b=0 ,
所以 a = - b
或 b = - a
分别代入原计算式得:
a-2b+ab-2ab
= a - b ( 2 + a)
= ( - b ) - b 〔 2 + ( - b )〕
= - 3 b + b ^2
= b ^2 - 3 b
或:
a-2b+ab-2ab
= a - b ( 2 + a)
= a - ( - a) ( 2 + a)
= a + 2a + a^2
= 3a + a ^2
= a ^2 + 3a
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