Question

设z=1+i(i是虚数的单位），侧2/z+z^2=?

Answer 1

2/z+z^2=2/(1+i)+(1+i)*(1+i)
=2(1-i)/((1+i)*(1-i))+(1+2i-i*i)
=(1-i)+2i
=1+i

Answer 2

2/z+z^2=1+i

追问

能把过程列得详细些吗

追答

2/z+z^2=2/(1+i)+(1+i)*(1+i)
=2(1-i)/((1+i)*(1-i))+(1+2i-i*i)
=2(1-i)/(1-i*i)+(1+2i-1)
=(1-i)+2i
=1+i