Question

如图,圆O的两条弦AB,CD交于点E,且AB⊥CD,AE=1,BE=3,O的半径为2.5,求CD长

图为：一圆O中，弦AB，弦CD互相垂直交于点E，且AB，CD不为直径。

Answer 1

算出来应该等于21开2次方，具体结算：从圆心o做ab、cd的垂线分别交ab和cd于f,g点，得ef=1，也就是og=1，连接oc解直角三角形得出gc的长度即可

Answer 2

AB=CD,且AB⊥CD于E,BE=7cm,AE=3cmOG⊥AB于G -

Answer 3

如图?

Answer 4

%D7%F6OF%A1%CDCD%0D%0A%A1%DF+%A1%CFAEC%3D45%A1%E3%0D%0A%A1%E0+%A1%F7EFO%CE%AA%B5%C8%D1%FC%D6%B1%BD%C7%C8%FD%BD%C7%D0%CE%0D%0A%A1%DFAE%3D1+BE%3D5+%0D%0A%A1%E0OE%3D2%0D%0A%A1%E0EF%3D%A1%CC2%0D%0A%D3%C9%CF%E0%BD%BB%CF%D2%B6%A8%C0%ED%B5%C3AE%2AEB%3DCE%2AED%3D5%0D%0AEF%2BCE%3DCD%2F2%0D%0ACE%3DCD%2F2-%A1%CC2%0D%0ADE%3DCD%2F2%2B%A1%CC2%0D%0ACE%2ADE%3D%28CD%2F2%29%26sup2%3B-2%3D5%0D%0ACD%3D2%A1%CC7