Question

求解下列热化学方程式

已知下列热化学方程式
1.fe2o3+3co(g)=2fe(s)+3co2(g) △H1=-25KJ/MOL
2.3fe2o3(s)+co(g)=2fe3o4(s)+co2(g) △H2=-47KJ/MOL
3.fe3o4(s)+co(g)=3feo(s)+co2(g) △H3=+19KJ/MOL

写出feo(s)被co还原成fe和 co2的热化学方程式

Answer 1

就是通过这几个热化学方程式的加加减减得到要求的方程式。

由第三个方程式可知：3FeO(s)+CO2(g)=Fe3O4(s)+CO(g) △H=-19KJ/mol ...(1)
由第二个方程式可知：2Fe3O4(s)+CO2(g)=3Fe2O3(s)+CO(g) △H=+47KJ/mol ...(2)
而第一个方程式：Fe2O3+3CO(g)=2Fe(s)+3CO2(g) △H=-25KJ/mol ...(3)

由 2*(1) + (2) + 3*(3)，消去等号两边相同的物质，可得：
6FeO(s)+6CO(g)=6Fe(s)+6CO2(g)，而对应的 △H=2*(-19)+47+3*(-25) = -66KJ/mol
消去6，可得：FeO(s)+CO(g)=Fe(s)+CO2(g) △H = -11KJ/mol

Answer 2

feo(s)+co(g) = fe(s)+co2(g) △H4=-11KJ/MOL

下面是过程:
3fe2o3+9co(g)=6fe(s)+9co2(g), △H1`=-75KJ/MOL
2fe3o4(s)+co2(g)=3fe2o3(s)+co(g), △H2`=47KJ/MOL
__________________
2fe3o4(s)+8co(g)=6fe(s)+8co2(g), △H0`=-28KJ/MOL

6feo(s)+2co2(g) =2fe3o4(s)+2co(g) △H3=-38KJ/MOL

_____________

Answer 3

1, 3fe2o3(s)+9co(g)=6fe(s)+9co2(g), △H1`=-75KJ/MOL
2. 2fe3o4(s)+co2(g)=3fe2o3(s)+co(g), △H2`=47KJ/MOL
4=1+2, 2fe3o4(s)+8co(g)=6fe(s)+8co2(g), △H1+2=-28KJ/MOL
3, 2fe3o4(s)+2co(g)=6feo(s)+2co2(g) △H3=+38KJ/MOL
4-3, 6feo(s)+6co(g) =6fe(s)+6co2(g) △H4-3=-66KJ/MOL
feo(s)+co(g) = fe(s)+co2(g) △H=-11KJ/MOL

Answer 4

① 3fe2o3(s)+9co(g)=6fe(s)+9co2(g), △H1=-75KJ/MOL
② 2fe3o4(s)+co2(g)=3fe2o3(s)+co(g), △H2=47KJ/MOL
④=①+② 2fe3o4(s)+8co(g)=6fe(s)+8co2(g), △H1+2=-28KJ/MOL
③ 2fe3o4(s)+2co(g)=6feo(s)+2co2(g) △H3=+38KJ/MOL
④-③ 6feo(s)+6co(g) =6fe(s)+6co2(g) △H4-3=-66KJ/MOL
feo(s)+co(g) = fe(s)+co2(g) △H=-11KJ/MOL

Answer 5

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(Reporter correspondent Gong Yuping Li Rui ) scene stunned the presence of residents , the police rescued the woman jumped to see the yellow great-grandmother , all excited applause .