Question

(a^m+1*b^n+2)(a^2n-1*b^2m)=a^5*b^3,求m+n=?

谢谢了

Answer 1

(a^m+1*b^n+2)(a^2n-1*b^2m)=a^（m+1+2n-1)*b^(n+2+2m)=a^5*b^3
所以m+1+2n-1=5,
n+2+2m=3,
解得m=-1
n=3
m+n=2.

Answer 2

(a^m+1*b^n+2)(a^2n-1*b^2m)=a^（m+1+2n-1)*b^(n+2+2m)=a^5*b^3
所以m+1+2n-1=2,
n+2+2m=3,
解得m=0
n=1
m+n=1.

Answer 3

(a^m+1*b^n+2)(a^2n-1*b^2m)=a^（m+1+2n-1）*b^（n+2+2m）=a^5*b^3
∴m+1+2n-1=5
n+2+2m=3
解得：m=-1
n=3
m+n=-1+3=2