Question

这道英文数学题怎么解？急求帮助！！！！！！！！！！！

Find the remainder R by long division and by the remainder theorem.

(2x4 - 10x2 + 30x - 60) ÷ (x + 4)

Answer 1

(1) Find the remainder R by long division
(2x^4 - 10x^2 + 30x - 60) ÷ (x + 4)

2x^3 - 8x^2 + 22x - 58
(2x^4 + 0 - 10x^2 + 30x - 60)
(x + 4) 2x^4 + 8x^3
-8x^3 - 10x^2
-8x^3 - 32x^2
22x^2 + 30x
22x^2 + 88x
- 58x - 60
- 58x - 232
172

(2x^4 - 10x^2 + 30x - 60) ÷ (x + 4)= 2x^3 - 8x^2 + 22x - 58 ..................R=172

(2) Find the remainder R by the remainder theorem
R = f(-4) = 2*(-4)^4 - 10*(-4)^2 +30*(-4) - 60 = 172

备注：昨晚解答，忽略了“and by the remainder theorem”。

Answer 2

就是求余数

Answer 3

remainder theorem就是余数定迟轮理码段信，根据余数燃颂定理，这个题应该等于f（-4），即2*（-4）^4-10*(-4）^2+30*(-4)-60=172